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dd10547ac2
The previous string construction discards two temporary std::string instances (operator+ returns by value, not by reference), and creates a std::string that it doesn't need to (the one around key). Instead we can just append to the end of the initial std::string itself, saving on two unnecessary created strings. append() has a const char* overload as well (as does operator+), so we can just append the key string as is without creating an entire new string.